fbpx
-30%

College Algebra, 8th Edition Robert F. Blitzer Solution Manual


College Algebra

( Solution Manual)

College Algebra, 8th Edition Robert F. Blitzer Solution Manual

Edition:8th Edition

Author Name:Robert F. Blitzer

contact:

 

Whatsapp +1 (949) 734-4773

 

for the Facebook page click here 

 

for more books  for  ( Test Bank and Solution Manual) click here

 

 

for Test bank  click here 

 

$35.00 $50.00

College Algebra

( Solution Manual)

College Algebra, 8th Edition Robert F. Blitzer Solution Manual

Edition:8th Edition

Author Name:Robert F. Blitzer

contact:

 

Whatsapp +1 (949) 734-4773

 

for the Facebook page click here 

 

for more books  for  ( Test Bank and Solution Manual) click here

 

 

for Test bank  click here 

 

sample free

 

Chapter P
Fundamental Concepts of Algebra
Copyright © 2022 Pearson Education, Inc 1
Section P.1
Check Point Exercises
1. 2 2 8 6( 3) 8 6(13 3) + − =+ − x

2 8 6(10)
8 6(100)
8 600
608
= +
= +
= +
=
2. a. Since 2016 is 16 years after 2000, substitute 16
for x. 2
2
361 3193
(16) 361(16) 3193
8713
Tx x =− + +
=− + +
=

The average cost of tuition and fees at public
U.S. colleges for the school year ending in
2016 was $8713.
b. The formula underestimates the actual answer
by $65.
3. The elements common to {3, 4, 5, 6, 7} and
{3, 7, 8, 9} are 3 and 7.
{3,4,5,6,7} {3,7,8,9} {3,7} ∩ =
4. The union is the set containing all the elements of
either set.
{3,4,5,6,7} {3,7,8,9} {3, 4,5,6,7,8,9} ∪ =
5. 9, 1.3, 0, 0.3, , 9, 10 2
  π   − −  
a. Natural numbers: 9 because 9 3 =
b. Whole numbers: 0, 9
c. Integers: −9, 0, 9
d. Rational numbers: − − 9, 1.3, 0, 0.3, 9
e. Irrational numbers: , 10
2
π
f. Real numbers: 9, 1.3, 0, 0.3, , 9, 10 2
π − −
6. a. 1 2 −
Because 2 1.4, ≈ the number inside the
absolute value bars is negative. The absolute
value of x when x < 0 is –x. Thus,
1 2 1 2 21 − =− − = − ( )
b. π −3
Because π ≈ 3.14, the number inside the
absolute value bars is positive. The absolute
value of a positive number is the number itself.
Thus,
π π −=− 3 3.
c.
x
x
Because x > = 0, . x x
Thus, 1
x x
x x = =
7. − − =− = 4 (5) 9 9
The distance between –4 and 5 is 9.
8. 2 2 7(4 3 ) 2(5 ) x ++ + x xx

2 2
2 2
2
7(4 3 ) 2(5 )
28 21 10 2
38 23
x x xx
x xxx
x x
= ++ +
= ++ +
= +
9. 6 4[7 ( 2)] + −−x

6 4[7 2)]
6 4[9 ]
6 36 4
42 4
x
x
x
x
=+ −+
=+ −
=+ −
= −
Concept and Vocabulary Check P.1
C1. expression
C2. b to the nth power; base; exponent
C3. formula; modeling; models
C4. intersection; A∩ B
C5. union; A∪

Based on 0 reviews

0.0 overall
0
0
0
0
0

Be the first to review “College Algebra, 8th Edition Robert F. Blitzer Solution Manual”

There are no reviews yet.

SHOPPING CART

close
WhatsApp chat